Find the Values of X and Y

Find the Values of X and Y

Observe the values of X and Y in the Given Equations

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Given two numbersandB      . Find the values of
X
and
Y
in the equations.

  1. A = X + Y
  2. B = X xor Y

The
chore
is to brand Ten equally minimum as possible. If it is non possible to observe any valid values for X and Y then print -i.
Examples:

          Input :
          A = 12, B = 8
          Output :
          X = 2, Y = x
          Input :
          A = 12, B = 9
          Output :
          -1

Let’s take a look at some bit in X, which is equal to 1. If the corresponding fleck in Y is equal to 0, then ane can swap these two $.25, thus reducing 10 and increasing Y without changing their sum and xor. Nosotros can conclude that if some bit in 10 is equal to 1 then the corresponding flake in Y is also equal to ane. Thus, Y = 10 + B. Taking into business relationship that X + Y = 10 + Ten + B = A, one can obtain the following formulas for finding X and Y:

  • X = (A – B) / ii
  • Y = X + B = (A + B) / 2

Ane should also detect that if
A < B
or A and B have unlike parity, so the answer doesn’t exist and output is -1. If Ten and (A – 10) not equal to X then the answer is also -one.
Below is the implementation of the above approach :

C++

#include <bits/stdc++.h>

using
namespace
std;

void
findValues(
int
a,

int
b)

{


if
((a - b) % ii == ane) {


cout <<

"-one"
;


return
;


}


cout << (a - b) / 2 <<

" "
<< (a + b) / 2;

}

int
main()

{


int
a = 12, b = eight;


findValues(a, b);


return
0;

}

Java

import
java.io.*;

class
GFG

{

static
void
findValues(
int
a,

int
b)

{


if
((a - b) %

two
==

1
)


{


System.out.println (
"-one"
);


return
;


}


Arrangement.out.println (((a - b) /

2
)+

" "
+


((a + b) /

2
));

}


public
static
void
principal (String[] args)


{


int
a =

12
, b =

8
;


findValues(a, b);


}

}

Python3

def
findValues(a, b):


if
((a

-
b)

%
two
=
=
ane
):


print
(
"-1"
);


return
;


impress
((a

-
b)

/
/
ii
, (a

+
b)

/
/
2
);

a

=
12
; b

=
8
;

findValues(a, b);

C#

using
System;

class
GFG

{

static
void
findValues(
int
a,

int
b)

{


if
((a - b) % 2 == i)


{


Console.Write (
"-1"
);


return
;


}


Console.WriteLine(((a - b) / 2)+

" "
+


((a + b) / 2));

}

static
public
void
Principal ()

{


int
a = 12, b = eight;


findValues(a, b);

}

}

PHP

<?php

function
findValues(
$a
,

$b
)

{


if
((
$a
-

$b
) % ii == 1)


{


echo
"-1"
;


return
;


}


echo
(
$a
-

$b
) / 2,

" "
,


(
$a
+

$b
) / 2;

}

$a
= 12;

$b
= 8;

findValues(
$a
,

$b
);

?>

Javascript

<script>

function
findValues(a, b)

{


if
((a - b) % 2 == i)


{


document.write(

"-i"
);


return
;


}


document.write( (a - b) / 2+

" "
+


(a + b) / 2);

}

let a = 12;

let b = 8;

findValues(a, b);

</script>

Fourth dimension Complexity: O(1), since there is only bones arithmetic that takes constant fourth dimension.
Auxiliary Infinite: O(1), since no extra space has been taken.

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Find the Values of X and Y

Source: https://www.geeksforgeeks.org/find-the-values-of-x-and-y-in-the-given-equations/